JEE Main 2020PhysicsCapacitanceMediumMCQ

JEE Main 2020 — Capacitance Question with Solution

JEE Main 2020 (05 Sep Shift 1)

Question

Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is :

Choose an option

Show full solutionCorrect option: B
Correct answer
B32CV2

Step-by-step explanation

Charge on C=CV
Charge on 2C=2C2V

From charge conservation, 2C(2V)-CV=(C+2C)V'
Common potential, V'=V
Final energy, Uf=12CV2+12×2CV2=32CV2

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About this question

This is a previous-year question from JEE Main 2020, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.