JEE Main 2019 — Capacitance Question with Solution

Two identical parallel plate capacitors, of capacitance $\mathrm{C}$ each, have plates of area $\mathrm{A},$ separated by a distance $\mathrm{d}$ . The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants ${\mathrm{K}}_1,\mathrm{ }{\mathrm{K}}_2$ and ${\mathrm{K}}_3$ . The first capaciitor is filled as shown in figure $\mathrm{I},$ and the second one is filled as shown in figure $\mathrm{I}\mathrm{I}.$
If these two modified capacitors are charged by the same potential $\mathrm{V}$ , the ratio of the energy stored in the two, would be $({\mathrm{E}}_1$ refers to capacitor $\left(\mathrm{I}\right)$ and ${\mathrm{E}}_2$ to capacitor $\left(\mathrm{I}\mathrm{I}\right)$ ):