JEE Main 2022PhysicsCapacitanceEasyMCQ

JEE Main 2022 — Capacitance Question with Solution

JEE Main 2022 (26 Jun Shift 1)

Question

Two capacitors having capacitance C1 and C2 respectively are connected as shown in figure. Initially, capacitor C1 is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor C1 is now connected to uncharged capacitor C2 by closing the switch S. The amount of charge on the capacitor C2, after equilibrium, is

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Show full solutionCorrect option: A
Correct answer
AC1C2C1+C2V

Step-by-step explanation

The initial charge on the capacitor C1 will be Q=C1V. If after closing the  switch the charge flown through the circuit is q, the charge on C2 will be q and C1 will be Q-q. The potential across the capacitors will be same. Hence,

Q-qC1=qC2⇒q=C2QC1+C2⇒q=C1C2C1+C2V

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About this question

This is a previous-year question from JEE Main 2022, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.