JEE Main 2023PhysicsCapacitanceEasyMCQ

JEE Main 2023 — Capacitance Question with Solution

JEE Main 2023 (11 Apr Shift 1)

Question

The electric field in an electromagnetic wave is given as
E→=20sinωt-xcj→N C-1, where ω and c are angular frequency and velocity of electromagnetic wave respectively. The energy contained in a volume of 5×10-4 m3 will be
(Given ε0=8.85×10-12C2 N-1 m-2)

Choose an option

Show full solutionCorrect option: D
Correct answer
D8.85×10-13 J

Step-by-step explanation

Given that, E→=20sinωt-xcj→N C-1

The average energy density of an electromagnetic wave is 12ε0E20.

The total energy stored is 

Etotal =12ε0E02× volume

⇒Etotal=12×8.85×10-12×(20)2×5×10-4=8.85×10-13 J

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About this question

This is a previous-year question from JEE Main 2023, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.