JEE Main 2019PhysicsCapacitanceEasyMCQ

JEE Main 2019 — Capacitance Question with Solution

JEE Main 2019 (09 Apr Shift 1)

Question

A capacitor with capacitance 5 μF is charged to 5 μC . If the plates are pulled apart to reduce the capacitance to 2 μF, how much work is done?

Choose an option

Show full solutionCorrect option: D
Correct answer
D3.75×10–6 J

Step-by-step explanation

Uinitial=Q22C1
Ufinal=Q22C2
Work done =Ufinal-Uinitial
=Q22C2-Q22C1
=5×10-622×2×10-6-5×10-622×5×10-6 
=254-52×10-6
=154×10-6 =3.75×10-6 J

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About this question

This is a previous-year question from JEE Main 2019, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.