JEE Main 2013 — Capacitance Question with Solution

A parallel plate capacitor having a separation between the plates $\mathrm{d}$, plate area $\mathrm{A}$ and material with dielectric constant $\mathrm{K}$ has capacitance ${\mathrm{C}}_0$. Now one-third of the material is replaced by another material with dielectric constant $2\mathrm{K}$, so that effectively there are two capacitors one with area $\frac{1}{3}\mathrm{A}$, dielectric constant $2\mathrm{K}$ and another with area $\frac{2}{3}\mathrm{A}$ and dielectric constant $\mathrm{K}$. If the capacitance of this new capacitor is $\mathrm{C}$ then $\frac{\mathrm{C}}{{\mathrm{C}}_0}$ is