JEE Main 2020PhysicsCapacitanceMediumMCQ

JEE Main 2020 — Capacitance Question with Solution

JEE Main 2020 (08 Jan Shift 1)

Question

Effective capacitance of parallel combination of two capacitors C1 and C2 is 10μF. When these capacitors are individually connected to a voltage source of 1V, the energy stored in the capacitor C2 is 4 times that of C1. If these capacitors are connected in series, their effective capacitance will be:

Choose an option

Show full solutionCorrect option: C
Correct answer
C1.6μF

Step-by-step explanation


Given C1+C2=10μF    ...(i)
412C1V2=12C2V2
⇒  4C1=C2...(ii)
From equation (i) and (ii)
C1=2μF
C2=8μF
If they are in series
Ceq=C1C2C1+2=1.6μF

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About this question

This is a previous-year question from JEE Main 2020, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.