JEE Main 2024PhysicsCenter of Mass Momentum and CollisionEasyMCQ

JEE Main 2024 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2024 (30 Jan Shift 1)

Question

A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5 m. The impulse of force imparted by the ground to the body is given by: (given g=9.8 m s-2)

Choose an option

Show full solutionCorrect option: D
Correct answer
D2.39 kg m s-1

Step-by-step explanation

Using equation of motion with constant acceleration, we can write:

v1=2gh1 and v2=2gh2

Now, required impulse

I→=Δp→=p→f-p→i

Given, M=0.1 kg

Therefore,

I=Δp=0.1(2×9.8×5-(-2×9.8×10))

=0.1(72+14)≈2.39 kg m s-1

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About this question

This is a previous-year question from JEE Main 2024, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.