JEE Main 2019PhysicsCenter of Mass Momentum and CollisionMediumMCQ

JEE Main 2019Center of Mass Momentum and Collision Question with Solution

JEE Main 2019 (08 Apr Shift 2)

Question

A uniform rectangular thin sheet ABCD of mass M has length a and breadth b, as shown in the figure. If the shaded portion HBGO is cut-off, the coordinates of the centre of mass of the remaining portion will be:

Choose an option

Show full solutionCorrect option: A
Correct answer
A5a12,5b12

Step-by-step explanation

If the total mass of object mass M then the mass removed part will be M4 .

XCM=M·a2-M43a4M-M4=Ma2-3Ma163M4=512a
YCM=M·b2-M43b4M-M4=Mb2-3Mb163M4=512b

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About this question

This is a previous-year question from JEE Main 2019, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.