JEE Main 2022PhysicsCenter of Mass Momentum and CollisionMediumMCQ

JEE Main 2022 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2022 (25 Jul Shift 2)

Question

Two billiard balls of mass 0.05 kg each moving in opposite directions with 10 ms-1 collide and rebound with the same speed. If the time duration of contact is t=0.005 s, then what is the force exerted on the ball due to each other?

Choose an option

Show full solutionCorrect option: B
Correct answer
B200 N

Step-by-step explanation

After collision, the balls change their directions of motion without changing the magnitudes of their velocity.

Change in momentum of any one ball

Δp→=2×0.05×10

⇒Δp→=1 kg m s-1

 The force exerted on the ball is F→av =Δp→Δt=10.005

Fav =200 N

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About this question

This is a previous-year question from JEE Main 2022, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.