JEE Main 2007 — Center of Mass Momentum and Collision Question with Solution
JEE Main 2007
Question
A circular disc of radius is removed from a bigger circular disc of radius such that the circumferences of the discs coincide. The centre of mass of the new disc is from the centre of the bigger disc. The value of is
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Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
In this question distance of centre of mass of new disc is not .
$\begin{aligned}
& -\frac{3 \mathrm{M}}{4} \alpha \mathrm{R}+\frac{\mathrm{M}}{4} \mathrm{R}=0 \\
& \Rightarrow \alpha=\frac{1}{3}
\end{aligned}$
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This is a previous-year question from JEE Main 2007, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.