JEE Main 2020 — Circular Motion Question with Solution
From: JEE Main 2020 (Online) 6th September Morning Slot
Question
A clock has a continuously moving second's hand of 0.1 m length. The average acceleration of the
tip of the hand (in units of ms–2) is of the order of :
Choose an option
Show full solutionCorrect option: A
Correct answer
A10-3
Step-by-step explanation
R = 0.1 m
= = = 0.105 rad/sec
a =
= (0.105)2(0.1)
= 0.0011
= 1.1 10-3
Average acceleration is of the order of 10–3.
= = = 0.105 rad/sec
a =
= (0.105)2(0.1)
= 0.0011
= 1.1 10-3
Average acceleration is of the order of 10–3.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Circular Motion chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Circular Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.