JEE Main 2020 — Circular Motion Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
A bead of mass m stays at point P(a, b) on a
wire bent in the shape of a parabola y = 4Cx2
and rotating with angular speed (see figure).
The value of is (neglect friction) :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
y = 4Cx2
= tan = 8Cx
At P, tan θ = 8Ca
For steady circular motion
mg sinθ = mω2acosθ
tan =
8Ca g = ω2a
=
=
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Circular Motion chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Circular Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.