JEE Main 2020 — Circular Motion Question with Solution
From: JEE Main 2020 (Online) 8th January Morning Slot
Question
A particle of mass m is fixed to one end of a
light spring having force constant k and
unstretched length . The other end is fixed. The
system is given an angular speed about the
fixed end of the spring such that it rotates in a
circle in gravity free space. Then the stretch in
the spring is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
At elongated position (x),
Fradial = mr
kx = m
x =
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This is a previous-year question from JEE Main 2020, covering the Circular Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.