JEE Main 2019PhysicsCircular MotionUniform Circular MotionmediumMCQ

JEE Main 2019Circular Motion Question with Solution

From: JEE Main 2019 (Online) 12th April Evening Slot

Question

A smooth wire of length 2r is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of 2 is equal to - JEE Main 2019 (Online) 12th April Evening Slot Physics - Circular Motion Question 60 English

This question includes a diagram. The text above accompanies the figure.

Choose an option

Show full solutionCorrect option: B
Correct answer
B

Step-by-step explanation

JEE Main 2019 (Online) 12th April Evening Slot Physics - Circular Motion Question 60 English Explanation
In ORP,

sin = = = sin 30o

= 30o

As the bead is at rest with respect to the circular ring at position P, The net force on bead is zero.

tan =

tan 30o =

=

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About this question

This is a previous-year question from JEE Main 2019, covering the Circular Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.