JEE Main 2020PhysicsElectromagnetic InductionMediumNumerical

JEE Main 2020 — Electromagnetic Induction Question with Solution

JEE Main 2020 (07 Jan Shift 1)

Question

A loop ABCDEFA of straight edges has six corner points A0,0,0,B5,0,0,C5,5,0,D0,5,0,E0,5,5 and F0,0,5 . The magnetic field in this region is B→=3i^+4k^T . The quantity of flux through the loop ABCDEFA (in Wb ) is _____________

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Show full solutionCorrect answer: 175
Correct answer
175

Step-by-step explanation

ϕ=B→.A→=3i^+4k^.25i^+25k^

ϕ=2×25+4×25=175weber

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About this question

This is a previous-year question from JEE Main 2020, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.