JEE Main 2019PhysicsElectromagnetic InductionEasyMCQ

JEE Main 2019 — Electromagnetic Induction Question with Solution

JEE Main 2019 (12 Jan Shift 2)

Question

A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 m s-1, at right angles to the horizontal component of the earth's magnetic field of 0.3×10-4 Wb m-2. The value of the induced emf in the wire is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B1.1×10-3 V

Step-by-step explanation

The wire makes an angle 45° with the magnetic field lines. Therefore, the induced emf will be,

ε=Bvlsin450

=0.3×10-4×5×10×12

=1.1×10-3 V

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About this question

This is a previous-year question from JEE Main 2019, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.