JEE Main 2023PhysicsElectromagnetic InductionEasyNumerical

JEE Main 2023 — Electromagnetic Induction Question with Solution

JEE Main 2023 (10 Apr Shift 1)

Question

A 1 m long metal rod XY completes the circuit as shown in figure. The plane of the circuit is perpendicular to the magnetic field of flux density 0.15 T. If the resistance of the circuit is 5 Ω, the force needed to move the rod in direction, as indicated, with a constant speed of 4 m s-1 will be _______10–3 N.

 

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Show full solutionCorrect answer: 18
Correct answer
18

Step-by-step explanation

The force on the rod is given by

F=ilB

⇒F=BvlR×lB

⇒F=B2l2vR   ...(i)

The data given is

R=5 Ωl=1 mv=4 m s-1B=0.15 T

Substituting the values in equation (i)

F=0.152×12×45

=18×10-3 N

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About this question

This is a previous-year question from JEE Main 2023, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.