JEE Main 2021PhysicsElectromagnetic InductionMediumNumerical

JEE Main 2021 — Electromagnetic Induction Question with Solution

JEE Main 2021 (27 Jul Shift 1)

Question

Consider an electrical circuit containing a two way switch S. Initially S is open and then T1 is connected to T2. As the current in R=6 Ω attains a maximum value of steady-state level, T1 is disconnected from T2 and immediately connected to T3. Potential drop across r=3 Ω resistor immediately after T1 is connected to T3 is ______V. (Round off to the Nearest Integer)

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

When T1 and T2 are connected, then the steady state current in the inductor I=66=1 A

When T1 and T3 are connected then current through inductor remains same. So potential difference across 3 Ω

V=Ir=1×3=3 V

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About this question

This is a previous-year question from JEE Main 2021, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.