JEE Main 2024 — Electromagnetic Waves Question with Solution
JEE Main 2024 (05 Apr Shift 2)
Question
Match List-I with List-II :
$\begin{array}{|c|c|c|c|}
\hline & \text { List-I } & & \text { List-II } \\
\hline & \text { EM-Wave } & & \text { Wavelength Range } \\
\hline \text { (A) } & \text { Infra-red } & \text { (I) } & < 10^{-3} \mathrm{~nm} \\
\hline \text { (B) } & \text { Ultraviolet } & \text { (II) } & 400 \mathrm{~nm} \text { to } 1 \mathrm{~nm} \\
\hline \text { (C) } & \text { X-rays } S & \text { (III) } & 1 \mathrm{~mm} \text { to } 700 \mathrm{~nm} \\
\hline \text { (D) } & \text { Gamma rays } & \text { (IV) } & 1 \mathrm{~nm} \text { to } 10^{-3} \mathrm{~nm} \\
\hline
\end{array}$
Choose an option
Show full solutionCorrect option: A
Correct answer
A(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
Step-by-step explanation
Infrared is the least energetic thus having biggest wavelength gamma rays are most energetic thus having smallest wavelength .
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This is a previous-year question from JEE Main 2024, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.