JEE Main 2017PhysicsElectromagnetic WavesEasyMCQ

JEE Main 2017 — Electromagnetic Waves Question with Solution

JEE Main 2017 (08 Apr Online)

Question

Magnetic field in a plane electromagnetic wave is given by,

B→=B0sinkx+ωtj^ T. Expression for corresponding electric field will be:

(Where c is speed of light)

Choose an option

Show full solutionCorrect option: C
Correct answer
CE→=B0csinkx+ωtk^ V m-1

Step-by-step explanation

For electromagnetic wave speed of light is given by

c=E0B0
Electric field is expressed as E0=cB0 , E→ is ⊥ to direction x and direction of B→

The expression of electric field is E→=cB0 sin⁡(kx+wt)k^  V m-1

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About this question

This is a previous-year question from JEE Main 2017, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.