JEE Main 2024PhysicsElectromagnetic WavesMediumMCQ

JEE Main 2024Electromagnetic Waves Question with Solution

JEE Main 2024 (27 Jan Shift 2)

Question

An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity 6×108 W m-2 falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space =3×108 m s-1 ):

Choose an option

Show full solutionCorrect option: C
Correct answer
C6 N m-2

Step-by-step explanation

The formula to calculate the radiation pressure is given by

P=Iv   ...1

Also, the velocity of the electromagnetic wave can be expressed as

μ=cv   ...2

Equations (1) and (2) imply that

P=I·μc=6×108×33×108=6 N m-2

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About this question

This is a previous-year question from JEE Main 2024, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.