JEE Main 2022PhysicsElectromagnetic WavesMediumMCQ

JEE Main 2022 — Electromagnetic Waves Question with Solution

JEE Main 2022 (24 Jun Shift 1)

Question

A plane electromagnetic wave travels in a medium of relative permeability 1.61 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5×10-2 A m-1 at a point, what will be the approximate magnitude of electric field intensity at that point ?

(Given : Permeability of free space μ0=4π×10-7 N A-2, speed of light in vacuum c=3×108 m s-1)

Choose an option

Show full solutionCorrect option: C
Correct answer
C8.48 V m-1

Step-by-step explanation

The speed of light in a given medium is given by,

v=cμrεr

Magnetic field is B=μrμ0H.

Also, the relation between the magnetic field and electric field is given by,

E=vB⇒E=cμrεr×μrμ0H=cεr×μr×μ0H⇒E=3×1086.44×1.61×4π×10-7×4.5×10-2=8.48 V m-1

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electromagnetic Waves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.