JEE Main 2022PhysicsElectromagnetic WavesEasyMCQ

JEE Main 2022 — Electromagnetic Waves Question with Solution

JEE Main 2022 (25 Jun Shift 1)

Question

The electric field in an electromagnetic wave is given by E=56.5sinωt-xcNC-1. Find the intensity of the wave if it is propagating along x-axis in the free space. (Given ϵ0=8.85×10-12C2 N-1 m-2) 

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Show full solutionCorrect option: C
Correct answer
C4.24  Wm-2

Step-by-step explanation

Given, E=56.5sinωt-xc N C-1

Comparing it with the general equation of electromagnetic wave, 

E=E0sin ωt-kx

We have, E0=56.5 N C-1

So, the intensity will be  I=12ε0E02c

=12×8.85×10-12×56.52×3×108

=4.24  W m-2

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About this question

This is a previous-year question from JEE Main 2022, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.