JEE Main 2014 — Electromagnetic Waves Question with Solution
JEE Main 2014 (09 Apr Online)
Question
| List I | List II | ||
|---|---|---|---|
| (a) | to | (i) | Vibration of atoms and molecules. |
| (b) | to | (ii) | Inner shell electrons in atoms moving from one energy level to a lower level. |
| (c) | (iii) | Radioactive decay of the nucleus. | |
| (d) | to | (iv) | Magnetron valve. |
Choose an option
Show full solutionCorrect option: B
Step-by-step explanation
We know, the range of wavelengths between , is referred as Infrared rays. These are produced by heating an object to such an extent that the molecules start vibrating and it radiates infrared waves. When the object is not hot enough such that it can emit visible light, therefore, it radiates Infrared waves.
Thus, option (a) in list I matches with Option (i) in list II.
The range of wavelengths between , is referred to as ultraviolet rays. Ultraviolet rays are produced due to atomic excitation in a gaseous discharge tube. This atomic excitation occurs when an atom from one energy level jumps to a lower energy level.
Thus, option (b) in list I matches with Option (ii) in list II.
The range of wavelengths are known as the Gamma rays. Some of the radioactive substances, when decay releases a spectrum, which falls in the range of , they emit electromagnetic waves called the gamma rays.
Thus, we can say, Thus, option (c) in list I matches with Option (iii) in list II.
We know again, the range of wavelength , is referred to as microwaves, and they are produced inside an oven in a tube like structure, called the magnetron.
Thus, we can say, option (d) in list I matches with Option (iv) in list II.
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This is a previous-year question from JEE Main 2014, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.