JEE Main 2022PhysicsElectromagnetic WavesMediumMCQ

JEE Main 2022 — Electromagnetic Waves Question with Solution

JEE Main 2022 (28 Jun Shift 2)

Question

An EM wave propagating in x-direction has a wavelength of 8 mm. The electric field vibrating y-direction has maximum magnitude of 60Vm-1. Choose the correct equations for electric and magnetic fields if the EM wave is propagating in vacuum :

Choose an option

Show full solutionCorrect option: B
Correct answer
B

Ey=60sinπ4×103x-3×108t j^ V m-1

Bz=2×10-7sinπ4×103x-3×108tk^ T

Step-by-step explanation

Using the relation E→=cB→, where, c is speed of light in vacuum.

After analysing each option, we get option B is the correct option

as E→B→=602×10-7=3×108 m s-1.

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About this question

This is a previous-year question from JEE Main 2022, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.