JEE Main 2020PhysicsElectromagnetic WavesEasyMCQ

JEE Main 2020 — Electromagnetic Waves Question with Solution

JEE Main 2020 (07 Jan Shift 1)

Question

If the magnetic field in a plane electromagnetic wave is given by B→=3×10-8sin⁡1.6×103x+48×1010tj^T, then what will be expression for electric field ?

Choose an option

Show full solutionCorrect option: B
Correct answer
BE→=9sin⁡1.6×103x+48×1010tk^Vm

Step-by-step explanation

E0B0=C (speed of light in vacuum)
E0=B0C=3×10-8×3×108
=9NC
So,

 E=9sin⁡ωt+kx+ϕ

E→=9sin⁡1.6×103x+48×1010tk ^Vm

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electromagnetic Waves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.