JEE Main 2024 — Electrostatics Question with Solution
JEE Main 2024 (09 Apr Shift 2)
Question
Five charges and are situated as shown in the figure. The electric flux due to this configuration through the surface is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
As per gauss theorem,
$\begin{aligned}& \phi=\frac{\mathrm{q}_{\text {in }}}{\epsilon_0}=\frac{\mathrm{q}+(-2 \mathrm{q})+5 \mathrm{q}}{\epsilon_0} \\
& \frac{4 \mathrm{q}}{\epsilon_0}\end{aligned}$
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electrostatics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2024, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.