JEE Main 2024PhysicsElectrostaticsEasyMCQ

JEE Main 2024Electrostatics Question with Solution

JEE Main 2024 (31 Jan Shift 2)

Question

Force between two point charges q1 and q2 placed in vacuum at r cm apart is F. Force between them when placed in a medium having dielectric K=5 at r5 cm apart will be:

Choose an option

Show full solutionCorrect option: B
Correct answer
B5F

Step-by-step explanation

Using Coulomb's law, we can write:

In air F=14πε0q1q2r2

In medium F'=14πKε0q1q2r'2=14π5ε025q1q2r2=5F

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About this question

This is a previous-year question from JEE Main 2024, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.