JEE Main 2022PhysicsElectrostaticsEasyMCQ

JEE Main 2022 — Electrostatics Question with Solution

JEE Main 2022 (27 Jul Shift 2)

Question

A charge of 4μC is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be:

Choose an option

Show full solutionCorrect option: B
Correct answer
B2μC and 2μC

Step-by-step explanation

If after division, one of the charge is q the other charge will be 4-q. The force between them can be written as,

F=Kq4-qd2

For the force between them to be maximum,

dFdq=0⇒Kd24-2q=0

⇒q=2 μC

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About this question

This is a previous-year question from JEE Main 2022, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.