JEE Main 2024PhysicsElectrostaticsEasyMCQ

JEE Main 2024Electrostatics Question with Solution

JEE Main 2024 (29 Jan Shift 1)

Question

Two charges of 5Q and -2Q are situated at the points (3a, 0) and (-5a, 0) respectively. The electric flux through a sphere of radius 4a having centre at origin is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B5Qε0

Step-by-step explanation

As can be seen from the figure above, only the 5Q charge is inside the spherical region.

The formula to calculate the flux through the surface is given by

ϕ=qencε0   ...1

From equation (1), the flux through the given surface can be calculated as follows:

ϕ=5Qε0

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electrostatics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.