JEE Main 2019PhysicsElectrostaticsMediumMCQ

JEE Main 2019 — Electrostatics Question with Solution

JEE Main 2019 (08 Apr Shift 1)

Question

A solid conducting sphere, having a charge Q, is surrounded by an uncharged conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of –4Q, the new potential difference between the same two surfaces is:

Choose an option

Show full solutionCorrect option: C
Correct answer
CV

Step-by-step explanation

First condition:

Both conducting spheres are shown.
Vin-Vout=KQr1-KQr2
⇒V=KQ1r1-1r2
Second condition:

Shell is now given charge -4Q .
Vin-Vout=KQr1-4KQr2-KQr2-4KQr2
=KQr1-KQr2
=KQ1r1-1r2=V

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About this question

This is a previous-year question from JEE Main 2019, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.