JEE Main 2023PhysicsElectrostaticsEasyNumerical

JEE Main 2023 — Electrostatics Question with Solution

JEE Main 2023 (08 Apr Shift 1)

Question

An electric dipole of dipole moment is 6.0 × 10-6 C m placed in a uniform electric field of 1.5 × 103 N C-1 in such a way that dipole moment is along electric field. The work done in rotating dipole by 180° in this field will be_______mJ.

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Show full solutionCorrect answer: 18
Correct answer
18

Step-by-step explanation

The work done for rotating a dipole is given by the change in the potential energy. The potential energy is given by

U=-p→·E→

W =∆U = Uf−Ui

So, the work done is 

 W=-pEcos180°-(-pEcos0°)=2pE=2×6×10-6×1.5×103=18 mJ

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About this question

This is a previous-year question from JEE Main 2023, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.