JEE Main 2022 — Electrostatics Question with Solution

A uniform electric field $E=\left(\frac{8m}{e}\right)\mathrm{V} {\mathrm{m}}^{-1}$ is created between two parallel plates of length $1 \mathrm{m}$ as shown in figure, (where $m=$ mass of electron and $e=$ charge of electron). An electron enters the field symmetrically between the plates with a speed of $2 \mathrm{m} {\mathrm{s}}^{-1}$. The angle of the deviation $\left(\theta \right)$ of the path of the electron as it comes out of the field will be _____ .