JEE Main 2024 — Electrostatics Question with Solution
JEE Main 2024 (06 Apr Shift 2)
Question
Two identical conducting spheres and with charge on each, repel each other with a force . A third identical uncharged conducting sphere is successively brought in contact with the two spheres. The new force of repulsion between and is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
$\begin{aligned} & F_{P S} \propto Q^2 \\ & F_{P S}=16 \mathrm{~N} \end{aligned}\mathrm{P} ~\&~ \mathrm{R}$ are brought in contact then
Now If are brought in contact then
New force between is : $\begin{aligned} & \mathrm{F}_{\mathrm{PS}} \propto \frac{\mathrm{Q}}{2} \times \frac{3 \mathrm{Q}}{4} \\ & \mathrm{~F}_{\mathrm{PS}} \propto \frac{3 \mathrm{Q}^2}{8}=\frac{3}{8} \times 16=6 \mathrm{~N} \end{aligned}$
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This is a previous-year question from JEE Main 2024, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.