JEE Main 2004 — Electrostatics Question with Solution
JEE Main 2004
Question
An -particle of energy is scattered through by a fixed uranium nucleus. The distance of the closest approach is of the order of
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
At closest approach, all the kinetic energy of the -particle will converted into the potential energy of the system, K.E. = P.E.
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This is a previous-year question from JEE Main 2004, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.