JEE Main 2022PhysicsExperimental PhysicsMediumNumerical

JEE Main 2022Experimental Physics Question with Solution

JEE Main 2022 (27 Jul Shift 1)

Question

The one division of main scale of vernier callipers reads 1 mm and 10 divisions of Vernier scale is equal to the 9 divisions on main scale. When the two jaws of the instrument touch each other the zero of the Vernier lies to the right of zero of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the zero of the Vernier scale lies in between 4.1 cm and 4.2 cm and 6th  Vernier division coincides with a main scale division. The diameter of the bob will be _____ 10-2 cm.

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Show full solutionCorrect answer: 412
Correct answer
412

Step-by-step explanation

Given,

1 MSD=1 mm

10 VSD=9 MSD

Then, 1 VSD=910MSD=0.9 MSD

Least count of Vernier calliper is L.C. =0.1 mm=0.01 cm

Positive zero error=0.4 mm =0.04 cm

Observed reading of diameter of spherical bob=4.1 cm+6×0.01=4.16 cm

Real reading of diameter of bob=4.16-0.04=4.12 cm =412×10-2 cm

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About this question

This is a previous-year question from JEE Main 2022, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.