JEE Main 2022PhysicsExperimental PhysicsEasyNumerical

JEE Main 2022Experimental Physics Question with Solution

JEE Main 2022 (28 Jun Shift 2)

Question

A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm,1.23 mm,1.19 mm and 1.20 mm. The percentage error is x121%. The value of x is _____ .

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Show full solutionCorrect answer: 150
Correct answer
150

Step-by-step explanation

The average value of the readings is xavg=1.19+1.20+1.22+1.234=1.21

Now, absolute error in measurement Δxavg=0.02+0.01+0.01+0.024=0.064=0.015

Percentage error in measurement is =0.0151.21×100%=150121%

So, the value of x=150.

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About this question

This is a previous-year question from JEE Main 2022, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.