JEE Main 2018PhysicsExperimental PhysicsEasyMCQ

JEE Main 2018 — Experimental Physics Question with Solution

JEE Main 2018 (15 Apr)

Question

In a screw gauge, 5 complete rotations of the screw cause it to move a linear distance of 0.25 cm. There are100 circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of 4 main scale divisions and 30 circular scale divisions. Assuming negligible error, the thickness of the wire is

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Show full solutionCorrect option: D
Correct answer
D0.2150 cm

Step-by-step explanation

The Least count=0.255×100 cm=5×10-4 cm.

Reading =4×0.05 cm+30×5×10-4 cm
              =0.2+0.0150 cm=0.2150 cm

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About this question

This is a previous-year question from JEE Main 2018, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.