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JEE Main 2024 — Experimental Physics Question with Solution

JEE Main 2024 (31 Jan Shift 2)

Question

The measured value of the length of a simple pendulum is 20 cm with 2 mm accuracy. The time for 50 oscillations was measured to be 40 seconds with 1 second resolution. From these measurements, the accuracy in the measurement of acceleration due to gravity is N%. The value of N is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C6

Step-by-step explanation

Time period of a simple pendulum is given by, T=2πlg.

⇒g=4π2lT2

Therefore, fractional error will be

Δgg=Δll+2ΔTT

=0.220+2140

=1.220

Percentage change =1.220×100=6%

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About this question

This is a previous-year question from JEE Main 2024, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.