JEE Main 2022PhysicsExperimental PhysicsMediumMCQ

JEE Main 2022 — Experimental Physics Question with Solution

JEE Main 2022 (26 Jul Shift 1)

Question

A screw gauge of pitch 0.5 mm is used to measure the diameter of uniform wire of length 6.8 cm, the main scale reading is 1.5 mm and circular scale reading is 7. The calculated curved surface area of wire to appropriate significant figures is
[Screw gauge has 50 divisions on the circular scale]

Choose an option

Show full solutionCorrect option: B
Correct answer
B3.4 cm2

Step-by-step explanation

Least Count (L.C)=PN=0.5 mm50=0.01 mm

Length of wire =6.8 cm

Diameter of wire =1.5 mm+7× L.C

=1.5 mm+7×.01=1.57 mm

Curved surface area =πDl

=3.14×6.8×1.57×10-1 cm2

=3.352 cm2=3.4 cm2

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About this question

This is a previous-year question from JEE Main 2022, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.