JEE Main 2022PhysicsKinetic Theory of GasesMediumNumerical

JEE Main 2022 — Kinetic Theory of Gases Question with Solution

JEE Main 2022 (29 Jul Shift 1)

Question

One mole of a monoatomic gas is mixed with three moles of a diatomic gas. The molecular specific heat of mixture at constant volume is α24R J mol K-1; then the value of α will be _____ . (Assume that the given diatomic gas has no vibrational mode.)

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

Molecular specific heat at constant volume in terms of degrees of freedom is given by CV=f2R

Molecular specific heat of mixture at constant volume is CV/mix=n1CV1+n2CV2n1+n2

=1×3R2+3×5R21+3

=9R4=α24R

⇒α=3

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About this question

This is a previous-year question from JEE Main 2022, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.