JEE Main 2023PhysicsKinetic Theory of GasesEasyMCQ

JEE Main 2023 — Kinetic Theory of Gases Question with Solution

JEE Main 2023 (06 Apr Shift 2)

Question

The temperature of an ideal gas is increased from 200 K to 800 K. If r.m.s. speed of gas at 200 K is v0. Then, r.m.s. speed of the gas at 800 K will be:

Choose an option

Show full solutionCorrect option: D
Correct answer
D2v0

Step-by-step explanation

At 200 K, the rms speed is given by

v0=3R×200M   ...(1)

At 800 K, the rms speed is given by

v'=3R×800M   ...2

Divide equation (2) by equation (1) and solve to calculate the required speed.

v'v0=3R×800M3R×200M=800200= 2⇒v'=2v0

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About this question

This is a previous-year question from JEE Main 2023, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.