JEE Main 2022PhysicsKinetic Theory of GasesEasyMCQ

JEE Main 2022 — Kinetic Theory of Gases Question with Solution

JEE Main 2022 (28 Jul Shift 1)

Question

Given below are two statements:

Statement I :The average momentum of a molecule in a sample of an ideal gas depends on temperature.

Statement II : The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v.

In the light of the above statements, choose the correct answer from the options given below :

Choose an option

Show full solutionCorrect option: D
Correct answer
DStatement I is false but Statement II is true

Step-by-step explanation

Momentum is a vector quantity and average momentum of molecules of a sample is zero due to random motion.

Pavg =0

RMS speed of a molecule is given by

vrms=3RTM

Now the temperature is doubled Tnew =2T and due to dissociation Mnew=M2.

⇒vnew v=2TM2TM

⇒vnew=2v

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About this question

This is a previous-year question from JEE Main 2022, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.