JEE Main 2024PhysicsKinetic Theory of GasesEasyMCQ

JEE Main 2024 — Kinetic Theory of Gases Question with Solution

JEE Main 2024 (27 Jan Shift 1)

Question

The average kinetic energy of a monatomic molecule is 0.414 eV at temperature:

(Use KB=1.38×10-23 J mol-1 K-1)

Choose an option

Show full solutionCorrect option: B
Correct answer
B3200 K

Step-by-step explanation

For monatomic molecule, degree of freedom =3.

The formula for the average kinetic energy is given by

Kavg=12f KBT   ...1

From equation (1), it follows that

0.414 eV×1.6×10-19 J1 eV=32×1.38×10-23 J mol-1 K-1×T⇒T=0.414 eV×1.6×10-19 J1 eV×23×1.38×10-23 J mol-1 K-1=3200 K

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About this question

This is a previous-year question from JEE Main 2024, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.