JEE Main 2024 — Kinetic Theory of Gases Question with Solution
JEE Main 2024 (06 Apr Shift 1)
Question
The specific heat at constant pressure of a real gas obeying equation is:
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
$\begin{aligned}
& \mathrm{dQ}=\mathrm{du}+\mathrm{dW} \\
& \mathrm{CdT}=\mathrm{C}_{\mathrm{V}} \mathrm{dT}+\mathrm{PdV} \\
& \therefore \mathrm{PV}^2=\mathrm{RT} \\
& \mathrm{P}=\text { constant } \\
& \mathrm{P}(2 \mathrm{VdV})=\mathrm{RdT} \\
& \mathrm{PdV}=\frac{\mathrm{RdT}}{2 \mathrm{~V}} \\
&
\end{aligned}$
Put in equation (1)
Put in equation (1)
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This is a previous-year question from JEE Main 2024, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.