JEE Main 2024PhysicsKinetic Theory of GasesMediumMCQ

JEE Main 2024Kinetic Theory of Gases Question with Solution

JEE Main 2024 (06 Apr Shift 1)

Question

The specific heat at constant pressure of a real gas obeying equation is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C

Step-by-step explanation

$\begin{aligned} & \mathrm{dQ}=\mathrm{du}+\mathrm{dW} \\ & \mathrm{CdT}=\mathrm{C}_{\mathrm{V}} \mathrm{dT}+\mathrm{PdV} \\ & \therefore \mathrm{PV}^2=\mathrm{RT} \\ & \mathrm{P}=\text { constant } \\ & \mathrm{P}(2 \mathrm{VdV})=\mathrm{RdT} \\ & \mathrm{PdV}=\frac{\mathrm{RdT}}{2 \mathrm{~V}} \\ & \end{aligned}$
Put in equation (1)

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Kinetic Theory of Gases chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.