JEE Main 2023PhysicsKinetic Theory of GasesEasyMCQ

JEE Main 2023 — Kinetic Theory of Gases Question with Solution

JEE Main 2023 (08 Apr Shift 2)

Question

The temperature at which the kinetic energy of oxygen molecules becomes double than its value at 27°C is

Choose an option

Show full solutionCorrect option: B
Correct answer
B327°C

Step-by-step explanation

The kinetic energy is given by KE=f2kT.

Let the kinetic energy be K1 at 27 °C and the kinetic energy be K' at T' temperature. As given in the question, K'=2K1. Hence, 

K'K1=T'T⇒2=T'300⇒T'=600 K

In Celsius the temperature is T'-273=327 °C.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Kinetic Theory of Gases chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Kinetic Theory of Gases chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.