JEE Main 2022PhysicsLaws of MotionEasyMCQ

JEE Main 2022 — Laws of Motion Question with Solution

JEE Main 2022 (26 Jul Shift 2)

Question

Two masses M1 and M2 are tied together at the two ends of a light inextensible string that passes over a frictionless pulley. When the mass M2 is twice that of M1. the acceleration of the system is a1. When the mass M2 is thrice that of M1. The acceleration of The system is a2. The ratio a1a2 will be

Choose an option

Show full solutionCorrect option: B
Correct answer
B23

Step-by-step explanation

In both cases m1>m2. Therefore, m1 will accelerate downward and m2 will accelerate upward.

For m1,

m1g-T=m1a

For m2,

T-m2g=m2a

Adding the above equations we get,

a=m1-m2m1+m2g

⇒a1=m1-m2m1+m2g=2m2-m22m2+m2g=g3

 and

⇒a2=m1-m2m1+m2g=3m2-m23m2+m2g=g2

⇒a1a2=23

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About this question

This is a previous-year question from JEE Main 2022, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.