JEE Main 2021PhysicsLaws of MotionMediumNumerical

JEE Main 2021 — Laws of Motion Question with Solution

JEE Main 2021 (17 Mar Shift 2)

Question

A body of mass 1 kg rests on a horizontal floor with which it has a coefficient of static friction 13. It is desired to make the body move by applying the minimum possible force F N. The value of F will be _______.(Round off to the Nearest Integer) [Take g=10 m s-2 ]

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Fcosθ=μN

⇒Fsinθ+N=mg

⇒F=μmgcosθ+μsinθ

Fmin=μmg1+μ2=13×1023=5

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About this question

This is a previous-year question from JEE Main 2021, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.