JEE Main 2024PhysicsLaws of MotionMediumMCQ

JEE Main 2024Laws of Motion Question with Solution

JEE Main 2024 (31 Jan Shift 1)

Question

In the given arrangement of a doubly inclined plane two blocks of masses M and m are placed. The blocks are connected by a light string passing over an ideal pulley as shown. The coefficient of friction between the surface of the plane and the blocks is 0.25. The value of m, for which M=10 kg will move down with an acceleration of 2 m s-2, is: (take g=10 m s-2 and tan 37°=34)

Choose an option

Show full solutionCorrect option: B
Correct answer
B4.5 kg

Step-by-step explanation

For M block:

10gsin53°-μ(10g) cos53°-T=10×2

T=80-15-20

T=45 N

For m block:

Tmg sin 37°-μ mg cos 37°=m×2

45=10 m

m=4.5 kg

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About this question

This is a previous-year question from JEE Main 2024, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.